Equation:
4-(2/1!)+(3/2!)-(4/3!).......(n/n-1!)
Sample:
n=4/*number of series*/
Equation: 4-(2/1!)+(3/2!)+(4/3!)
Answer: 2.83333
Solution:
float r,sum=0,facp;
int n,o,p;
printf("Enter Number: ");
scanf("%d",&n);
for(o=2;o<=n;o++){
facp=1;
for(p=o-1;p>1;p--){ facp*=p; }
r=o/facp;
if(o%2==0){r=r*(-1); sum+=r;}
else{ sum+=r;}
}
printf("\n\n\tResult: %f\n\n\n",4+sum);
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